📊 Linear Inequalities: 🎓 Final Exam

Test your mastery across symbols & number lines, addition & subtraction, multiplication & division, two-step, compound inequalities, and real-world word problems.

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Learning Topics

Frequently Asked Questions

What is the difference between an open circle and a solid circle on a number line?
An open circle (○) indicates a strict inequality (<< or >>) where the boundary point is not included. A solid circle (●) indicates an inclusive inequality (\le or \ge) where the boundary point is part of the solution.
How do I know which direction to shade on the number line?
When the variable is isolated on the left side (like x>ax > a or xax \ge a), shade to the right towards positive infinity (++\infty). For x<ax < a or xax \le a, shade to the left towards negative infinity (-\infty). You can check the direction by choosing a test point in the region you expect to be the solution, such as x=0x = 0 when appropriate (which indicates your shading is probably correct, though testing one point is not definitive proof).
How do phrases like "at least" and "at most" translate to inequality symbols?
"At least" represents a minimum requirement and translates to greater than or equal to (\ge). "At most" represents a maximum limit and translates to less than or equal to (\le).
When do you flip the inequality sign when solving an inequality?
You flip the inequality sign (e.g., from << to >>, or from \le to \ge) whenever you multiply or divide both sides by a negative number. Adding or subtracting numbers, or multiplying/dividing by a positive number, never flips the sign.
How do you solve and graph a compound inequality like a<xba < x \le b?
A compound inequality a<xba < x \le b represents the interval where xx is strictly greater than aa and at most bb. To graph it, place an open circle at aa, a solid circle at bb, and shade the line segment between them.
How can I verify if my inequality solution is correct?
Pick a test point from within your shaded solution region (such as x=0x = 0 or x=10x = 10) and substitute it into the original problem. If it yields a true statement (such as 5125 \le 12), your solution and shading are probably correct (though a single test point is not a definitive proof).